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The factorization of x2y2 + xy + xy2z + yz + x2yz + xz is

Question

The factorization of x2y2 + xy + xy2z + yz + x2yz + xz is

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Solution

To factorize the expression x2y2 + xy + xy2z + yz + x2yz + xz, we can follow these steps:

Step 1: Group the terms with common factors. x2y2 + xy + xy2z + yz + x2yz + xz = (x2y2 + xy) + (xy2z + yz) + (x2yz + xz)

Step 2: Factor out the common factors from each group. = xy(x + 1) + yz(xy + 1) + xz(xy + 1)

Step 3: Notice that (xy + 1) is a common factor in all three terms. = (xy + 1)(x + yz + xz)

Therefore, the factorization of x2y2 + xy + xy2z + yz + x2yz + xz is (xy + 1)(x + yz + xz).

This problem has been solved

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