The mean serum urate concentration (from uric acid) in a sample of urine was measured to be 64 mg/L. If a 2.0 mL aliquot of the urine sample is analyzed, what is the total mass of the serum urate present in the aliquot?A.3.2 × 10−5 gB.1.3 × 10−4 gC.3.2 × 10−2 gD.1.3 × 10−1 g
Question
The mean serum urate concentration (from uric acid) in a sample of urine was measured to be 64 mg/L. If a 2.0 mL aliquot of the urine sample is analyzed, what is the total mass of the serum urate present in the aliquot?A.3.2 × 10−5 gB.1.3 × 10−4 gC.3.2 × 10−2 gD.1.3 × 10−1 g
Solution
To solve this problem, we need to convert the concentration of serum urate from mg/L to g/mL, and then multiply it by the volume of the aliquot.
-
Convert the concentration from mg/L to g/mL. There are 1000 mg in 1 g, and 1 L is equal to 1000 mL. So, 64 mg/L is equal to 64/1000 g/L, which is 0.064 g/L. Since 1 L = 1000 mL, we can further convert this to 0.064/1000 g/mL, which is 0.000064 g/mL.
-
Multiply the concentration by the volume of the aliquot. The volume of the aliquot is 2.0 mL, so the total mass of the serum urate in the aliquot is 0.000064 g/mL * 2.0 mL = 0.000128 g.
So, the answer is closest to B. 1.3 × 10−4 g.
Similar Questions
A lowered level of sodium ions in the blood of the average female adult would be 0.125 mol L-1 and would be cause for concern. The average adult female has a total blood volume of 4.60 L. Calculate the total mass of sodium ions present when this concentration is found, assuming a blood volume of 4.60 L. Question 5Select one:a.13.2 gb.33.6 gc.1.60 gd.0.625 ge.40.0 gf.2.87 g
A water sample has a total dissolved solids (TDS) concentration of 500 milligrams per liter (mg/L). What is the total mass of dissolved solids (in kilograms) in 1,000 liters of the water sample?a.0.5 kgb.5 kgc.50 kg
An analytical chemist weighs out 0.163g of an unknown monoprotic acid into a 250mL volumetric flask and dilutes to the mark with distilled water. She then titrates this solution with 0.1300M NaOH solution. When the titration reaches the equivalence point, the chemist finds she has added 16.5mL of NaOH solution.Calculate the molar mass of the unknown acid. Round your answer to 3 significant digits.
When excess dilute HCL was added to sodium sulphate, 960cm^3 of sulphuric(iv)oxide gas was produced. Calculate the mass of sodium sulphate that was used (Molar gas volume=24000cm^3 and molar mass of sulphate=126g)
A second-year chemistry student is asked to make up a 500.0 mL sample of 0.057 M solution of aspirin to study the rate of hydrolysis of aspirin in the digestive system. Molar mass of Aspirin, acetylsalicylic acid, C9H8O4 = 180.17 g mol-1. (a) Calculate the mass (in grams) of aspirin that the student would need to weigh out. Provide your numerical answers and units.
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.