Select the correct answer What will be the output of the following pseudocode for a = 3, b = 2 ? Integer funn ( integer a, integer b ) if ( b ^ a > (( a + 1) ^ ( b + 1 ))) a= a & b else b = a + 1 end if return a+ b end function funn ( ) radio_button_unchecked 4 radio_button_unchecked 5 radio_button_unchecked 47 radio_button_unchecked 56
Question
Select the correct answer What will be the output of the following pseudocode for a = 3, b = 2 ?
Integer funn ( integer a, integer b ) if ( b ^ a > (( a + 1) ^ ( b + 1 ))) a= a & b else b = a + 1 end if return a+ b end function funn ( ) radio_button_unchecked 4
radio_button_unchecked 5
radio_button_unchecked 47
radio_button_unchecked 56
Solution
First, let's understand the pseudocode:
The function funn takes two integers a and b as input. In this case, a = 3 and b = 2.
The first operation is a bitwise XOR operation between b and a. In binary, 3 is 11 and 2 is 10. The XOR operation gives us 01, which is 1 in decimal.
The second operation is a bitwise XOR operation between (a + 1) and (b + 1). In this case, (a + 1) is 4 and (b + 1) is 3. In binary, 4 is 100 and 3 is 11. The XOR operation gives us 111, which is 7 in decimal.
The if condition checks if the result of the first operation is greater than the result of the second operation. In this case, 1 is not greater than 7, so the else part of the if condition is executed.
In the else part, b is assigned the value of a + 1, which is 4.
Finally, the function returns the sum of a and b, which is 3 + 4 = 7.
So, the correct answer is not listed in the options.
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