What output will the following Python program produce?n = 10while n != 1: print (n,) if n % 2 == 0: # n is even n = n // 2 else: # n is odd n = n * 3 + 1Question 10Select one:a.10 5 16 8 4 2b.None an error will be displayedc.8 4 2d.9 28 14 7 22 11 34 17 52 26 13 40 20 10 5 16 8 4 2
Question
What output will the following Python program produce?n = 10while n != 1: print (n,) if n % 2 == 0: # n is even n = n // 2 else: # n is odd n = n * 3 + 1Question 10Select one:a.10 5 16 8 4 2b.None an error will be displayedc.8 4 2d.9 28 14 7 22 11 34 17 52 26 13 40 20 10 5 16 8 4 2
Solution
The output of the given Python program will be:
10 5 16 8 4 2
So, the correct answer is option a. 10 5 16 8 4 2
Here's the step by step explanation:
- The program starts with n = 10.
- It enters the while loop because n is not equal to 1.
- It prints the current value of n, which is 10.
- Since n is even, it divides n by 2 and assigns the result back to n. Now, n is 5.
- The loop continues with n = 5. It prints 5.
- Since n is odd, it multiplies n by 3 and adds 1, assigning the result back to n. Now, n is 16.
- The loop continues with n = 16, 8, 4, and 2, following the same rules.
- When n becomes 1, the loop ends, and the program stops printing numbers.
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