Percentage covalent character is higher inA NaF B NaCl C NaBr D NaI

The percentage covalent character in a bond is determined by the difference in electronegativity between the two atoms involved. The greater the difference, the more ionic the bond is, and the smaller the difference, the more covalent the bond is.

1. Identify the electronegativity of each atom involved in the bond. The electronegativity values for Sodium (Na), Fluorine (F), Chlorine (Cl), Bromine (Br), and Iodine (I) are approximately 0.93, 3.98, 3.16, 2.96, and 2.66 respectively.

2. Calculate the difference in electronegativity for each bond.

   • NaF: 3.98 - 0.93 = 3.05
   • NaCl: 3.16 - 0.93 = 2.23
   • NaBr: 2.96 - 0.93 = 2.03
   • NaI: 2.66 - 0.93 = 1.73

3. Compare the differences. The bond with the smallest difference in electronegativity will have the highest percentage of covalent character.

From the calculations, NaI has the smallest difference in electronegativity, so it has the highest percentage of covalent character among the options given. Therefore, the answer is D, NaI.