The pseudo code provided is a bit confusing due to the lack of proper indentation and formatting. However, I'll try to explain it as best as I can.

First, we initialize three variables a, b, and c with the values 3, 4, and 10 respectively.

Then, we set a to be equal to 10 + b, which is 14.

Next, we have an if statement that checks if (a + b + c) is less than (b + c + a). This condition will always be false because both sides of the inequality are the same (they both add up to the same value). Therefore, the code inside this if statement will not be executed.

Since the condition in the first if statement is false, we move to the else part. Here, we have another if statement that checks if (b + c) is less than (c - b). This condition is also false because (b + c) is greater than (c - b). Therefore, the code inside this if statement will not be executed either.

Finally, we set a to be equal to 10 + b, which is 14.

So, the final values of a, b, and c are 14, 4, and 10 respectively.

Therefore, the output of the pseudo code when we print a + b + c will be 14 + 4 + 10 = 28.

Question

The pseudo code provided is a bit confusing due to the lack of proper indentation and formatting. However, I'll try to explain it as best as I can.

First, we initialize three variables a, b, and c with the values 3, 4, and 10 respectively.

Then, we set a to be equal to 10 + b, which is 14.

Next, we have an if statement that checks if (a + b + c) is less than (b + c + a). This condition will always be false because both sides of the inequality are the same (they both add up to the same value). Therefore, the code inside this if statement will not be executed.

Since the condition in the first if statement is false, we move to the else part. Here, we have another if statement that checks if (b + c) is less than (c - b). This condition is also false because (b + c) is greater than (c - b). Therefore, the code inside this if statement will not be executed either.

Finally, we set a to be equal to 10 + b, which is 14.

So, the final values of a, b, and c are 14, 4, and 10 respectively.

Therefore, the output of the pseudo code when we print a + b + c will be 14 + 4 + 10 = 28.

Knowee AI · Accepted Answer

The pseudo code provided is a bit confusing due to the lack of proper indentation and formatting. However, I'll try to explain it as best as I can.

First, we initialize three variables a, b, and c with the values 3, 4, and 10 respectively.

Then, we set a to be equal to 10 + b, which is 14.

Next, we have an if statement that checks if (a + b + c) is less than (b + c + a). This condition will always be false because both sides of the inequality are the same (they both add up to the same value). Therefore, the code inside this if statement will not be executed.

Since the condition in the first if statement is false, we move to the else part. Here, we have another if statement that checks if (b + c) is less than (c - b). This condition is also false because (b + c) is greater than (c - b). Therefore, the code inside this if statement will not be executed either.

Finally, we set a to be equal to 10 + b, which is 14.

So, the final values of a, b, and c are 14, 4, and 10 respectively.

Therefore, the output of the pseudo code when we print a + b + c will be 14 + 4 + 10 = 28.

What will be output of the following pseudo code ?Integer a, b, c Set a=3, b=4,c=10a=10+b if ((a+b+c)<(b+c+a)) a=(3+9)+c if ((b+a+7)<(5+c+b)) c=(b+11)+c Else a=(8+5)+a End if b=(2+2)+bElse if ((b+c)<(c-b)) b=(a+b)+b c=c+b End if a=10+bEnd if print a+b+c

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