In a first-order reaction A B , if k is the rate constant and initial concentration of thereactant A is 0.5 M, then the half-life i
Question
In a first-order reaction A B , if k is the rate constant and initial concentration of thereactant A is 0.5 M, then the half-life i
Solution
To determine the half-life of a first-order reaction A B, we need to use the rate constant (k) and the initial concentration of reactant A (0.5 M).
Step 1: Recall the first-order reaction rate equation: Rate = k[A]
Step 2: The half-life (t1/2) is the time it takes for the concentration of reactant A to decrease by half. Mathematically, it can be calculated using the equation: t1/2 = (0.693 / k)
Step 3: Substitute the given initial concentration of reactant A (0.5 M) into the rate equation: Rate = k[0.5]
Step 4: Rearrange the rate equation to solve for the rate constant (k): k = Rate / [0.5]
Step 5: Substitute the value of k into the half-life equation: t1/2 = (0.693 / (Rate / [0.5]))
Step 6: Simplify the equation: t1/2 = (0.693 * [0.5]) / Rate
Step 7: Calculate the half-life using the given rate constant (k) and initial concentration of reactant A (0.5 M).
Please note that the specific value of the rate constant (k) is not provided in the question, so you would need that information to calculate the half-life accurately.
Similar Questions
The half-life for a zero order reaction having 0.02 M initial concentration of reactant is 100 s. The rate constant (in mol L−1 s−1) for the reaction is
For a first-order reaction, the half-life is defined as the time required for the concentration of the reactant to decrease to _____ of its initial value.Select one:a.50%b.75%c.25%d.10%
Rate of Reaction: Rate = - Δ[Reactant]/Δt = Δ[Product]/Δt Rate Law: Rate = k[A]^x[B]^y First Order Reaction: ln[A]t = -kt + ln[A]0 Second Order Reaction: 1/[A]t = kt + 1/[A]0 Zero Order Reaction: [A]t = -kt + [A]0 Half-Life (t1/2) for First Order Reaction: t1/2 = 0.693/k Half-Life (t1/2) for Second Order Reaction: t1/2 = 1/(k[A]0) Half-Life (t1/2) for Zero Order Reaction: t1/2 = [A]0/2k Arrhenius Equation: k = Ae^(-Ea/RT) where A is the pre-exponential factor, Ea is the activation energy, R is the gas constant, and T is the temperature in Kelvin. Integrated Rate Law for First Order Reaction: ln([A]0/[A]t) = kt Integrated Rate Law for Second Order Reaction: 1/[A]t - 1/[A]0 = kt Integrated Rate Law for Zero Order Reaction: [A]0 - [A]t = kt
The rate constant for a second-order reaction is 0.54 M-1s-1. What is the half-life of this reaction if the initial concentration is 0.51 M?Group of answer choices3.6 s1.3 s2.8 s1.1 s0.94 s
Half life is inversely proportional to concentration in which order kinetics
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.