What is the output of the following code?int arr[] = {1, 2, 3, 4, 5};int i;for (i = 0; i < 5; i++) arr[i] = arr[i] + 2;printf("%d\n", arr[3]);
Question
What is the output of the following code?int arr[] = {1, 2, 3, 4, 5};int i;for (i = 0; i < 5; i++) arr[i] = arr[i] + 2;printf("%d\n", arr[3]);
Solution
The output of the code will be 6.
Here's the step by step explanation:
-
An integer array
arris declared and initialized with the values{1, 2, 3, 4, 5}. -
A for loop is set up to iterate over the array from the first element (at index 0) to the last element (at index 4).
-
Inside the loop, each element of the array is incremented by 2. So, the array becomes
{3, 4, 5, 6, 7}. -
After the loop, the value of the element at index 3 (which is the fourth element) of the array is printed. Since arrays are 0-indexed,
arr[3]refers to the fourth element of the array, which is 6.
So, the output of the code is 6.
Similar Questions
Consider the following code snippet. What is the output?#include <stdio.h>int main() { int arr[5] = {1, 2}; for (int i = 0; i < 5; i++) { printf("%d ", arr[i]); } return 0;}
What is the output of the following code?#include <stdio.h>int main() { int arr[] = {1, 2, 3, 4, 5}; int *p = arr; printf("%d\n", *(p + 3)); return 0;}
What will be the output of the following code?#include <stdio.h>int main() { int arr[4] = {0, 1, 2, 3}; printf("%d\n", arr[-1]); return 0;}
.What will be the output of the following C code?int main() {int arr[] = {1, 2, 3, 4, 5};printf("%d", arr[3]);return 0;}*1 point1234
What is the output of the following code?#include <stdio.h>void modifyArray(int arr[], int size) { for (int i = 0; i < size; i++) { arr[i] = arr[i] * 2; }}int main() { int arr[] = {1, 2, 3, 4, 5}; int size = sizeof(arr) / sizeof(arr[0]); modifyArray(arr, size); printf("%d\n", arr[2]); return 0;}
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.