If a transformer have turn ratio 5, frequency 50 Hz, root mean square value of potential difference on primary winding is 100 volts and the resistance of the secondary winding is 500 then the peak value of voltage in secondary winding will be (the efficiency of the transformer is hundred percent)-
Question
If a transformer have turn ratio 5, frequency 50 Hz, root mean square value of potential difference on primary winding is 100 volts and the resistance of the secondary winding is 500 then the peak value of voltage in secondary winding will be (the efficiency of the transformer is hundred percent)-
Solution
The peak value of the voltage in the secondary winding of a transformer can be calculated using the formula:
Vp = Vrms * sqrt(2)
Where: Vp is the peak voltage, Vrms is the root mean square voltage.
However, before we can use this formula, we need to find the root mean square voltage of the secondary winding. This can be found using the turn ratio of the transformer. The turn ratio is the ratio of the number of turns in the primary winding to the number of turns in the secondary winding. In this case, the turn ratio is 5.
So, the root mean square voltage of the secondary winding (Vrms2) can be calculated as:
Vrms2 = Turn ratio * Vrms1
Where: Vrms1 is the root mean square voltage of the primary winding.
Substituting the given values:
Vrms2 = 5 * 100 = 500 volts
Now we can calculate the peak voltage of the secondary winding:
Vp = Vrms2 * sqrt(2) = 500 * sqrt(2) = 707.1 volts
So, the peak value of the voltage in the secondary winding is approximately 707.1 volts.
Similar Questions
A transformer has 400 turns on the primary and 100 turns on the secondary. If 120 volts AC are applied across the primarywindings, calculate the voltage induced in the secondary.
A half wave rectifier has a 200V rms. source and thestep-down transformerhas a turns ratioof41.What will be the peak voltage across the load ignoring the drop across the diodeChoose the best optionClear Response70.7V40V30V50V
Question 2List three functions which a transformer may perform in an electrical circuit. [3 marks]A 10kVA, 50 Hz distribution transformer has 600 turns in the primary and 120 turns in thesecondary. The primary and secondary resistances are r1 = 0.2 Ω and r 2 = 0.02 Ω respectively,and the corresponding leakage reactances are Xl1 = 1.0 Ω, and Xl2 = 0.04 Ω respectively. Thesupply voltage is 1100V.Calculate(a) The equivalent impedance, resistance and reactance, referring all quantities to thehigh voltage (primary) side; [6 marks](b) The secondary terminal voltage for full load having a power factor of 0.7 lagging;Draw the phasor diagram; [7 marks](c) The regulation in (b) [4 marks]2130310310
Power transformers are designed to have maximum efficiency at
The core loss of a 5KVA single phase transformer with normal voltage applied to the primary is 74 watts. The maximum efficiency occurs at 70% of full-load KVA. What is the full load efficiency of the transformer at untiy power factor?
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.