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What does the following Python code snippet do?def delete_node(self, key):    temp = self.head    if temp is not None:        if temp.data == key:            self.head = temp.next            temp = None            return    while temp is not None:        if temp.data == key:            break        prev = temp        temp = temp.next    if temp == None:        return    prev.next = temp.next    temp = NoneDeletes the first occurrence of a node with the specified keyDeletes all nodes with the specified keyInserts a node with the specified key at the beginning of the linked listReverses the linked list

Question

What does the following Python code snippet do?def delete_node(self, key):    temp = self.head    if temp is not None:        if temp.data == key:            self.head = temp.next            temp = None            return    while temp is not None:        if temp.data == key:            break        prev = temp        temp = temp.next    if temp == None:        return    prev.next = temp.next    temp = NoneDeletes the first occurrence of a node with the specified keyDeletes all nodes with the specified keyInserts a node with the specified key at the beginning of the linked listReverses the linked list

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Solution

The provided Python code snippet is a function for deleting the first occurrence of a node with a specified key in a linked list. Here's a step-by-step explanation:

  1. The function delete_node(self, key) is defined. It takes two parameters: self and key. self is a reference to the instance of the class, and key is the value that you want to delete from the linked list.

  2. The function starts by setting a temporary variable temp to the head of the linked list.

  3. It then checks if the head of the linked list is not None (i.e., the linked list is not empty).

  4. If the head of the linked list contains the key to be deleted, the function sets the head of the linked list to be the next node and deletes the current head node by setting temp to None.

  5. If the head of the linked list does not contain the key to be deleted, the function enters a while loop that continues until it finds a node with the key to be deleted or it reaches the end of the linked list.

  6. Inside the while loop, if a node with the key to be deleted is found, the loop is broken.

  7. If the loop completes without finding a node with the key to be deleted (i.e., temp is None), the function returns and does nothing.

  8. If a node with the key to be deleted is found, the function sets the next attribute of the previous node to be the node after temp, effectively skipping over temp and removing it from the linked list. It then deletes temp by setting it to None.

So, the correct answer is: "Deletes the first occurrence of a node with the specified key".

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