What does the following Python code snippet do?def delete_node(self, key): temp = self.head if temp is not None: if temp.data == key: self.head = temp.next temp = None return while temp is not None: if temp.data == key: break prev = temp temp = temp.next if temp == None: return prev.next = temp.next temp = NoneDeletes the first occurrence of a node with the specified keyDeletes all nodes with the specified keyInserts a node with the specified key at the beginning of the linked listReverses the linked list
Question
What does the following Python code snippet do?def delete_node(self, key): temp = self.head if temp is not None: if temp.data == key: self.head = temp.next temp = None return while temp is not None: if temp.data == key: break prev = temp temp = temp.next if temp == None: return prev.next = temp.next temp = NoneDeletes the first occurrence of a node with the specified keyDeletes all nodes with the specified keyInserts a node with the specified key at the beginning of the linked listReverses the linked list
Solution
The provided Python code snippet is a function for deleting the first occurrence of a node with a specified key in a linked list. Here's a step-by-step explanation:
-
The function
delete_node(self, key)is defined. It takes two parameters:selfandkey.selfis a reference to the instance of the class, andkeyis the value that you want to delete from the linked list. -
The function starts by setting a temporary variable
tempto the head of the linked list. -
It then checks if the head of the linked list is not
None(i.e., the linked list is not empty). -
If the head of the linked list contains the key to be deleted, the function sets the head of the linked list to be the next node and deletes the current head node by setting
temptoNone. -
If the head of the linked list does not contain the key to be deleted, the function enters a while loop that continues until it finds a node with the key to be deleted or it reaches the end of the linked list.
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Inside the while loop, if a node with the key to be deleted is found, the loop is broken.
-
If the loop completes without finding a node with the key to be deleted (i.e.,
tempisNone), the function returns and does nothing. -
If a node with the key to be deleted is found, the function sets the
nextattribute of the previous node to be the node aftertemp, effectively skipping overtempand removing it from the linked list. It then deletestempby setting it toNone.
So, the correct answer is: "Deletes the first occurrence of a node with the specified key".
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