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est the convergence of theseries 1 + ๐‘ฅ2 + ๐‘ฅ25 + ๐‘ฅ310 + โ‹ฏ

Question

est the convergence of theseries 1 + ๐‘ฅ2 + ๐‘ฅ25 + ๐‘ฅ310 + โ‹ฏ

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Solution

The series you've given is a geometric series with a common ratio of x^23.

The convergence of a geometric series is determined by the absolute value of the common ratio. If the absolute value of the common ratio is less than 1, the series converges. If the absolute value of the common ratio is greater than or equal to 1, the series diverges.

So, for the series to converge, we need |x^23| < 1.

This inequality holds for all x in the interval (-1, 1).

Therefore, the series converges for all x in the interval (-1, 1) and diverges for all other x.

This problem has been solved

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est the convergence of theseries 1 + ๐‘ฅ2 + ๐‘ฅ25 + ๐‘ฅ310 + โ‹ฏ

Describe Convergence of IT and OT.

Exercise nยฐ1Identify the pattern of the following sequence.1, 1, 2, 3, 5, 8, 13, . ..Exercise nยฐ2Write out the first four items of the sequences whose general terms are:a. ๐‘Ž๐‘Ž ๐‘›๐‘› = 2๐‘›๐‘› + 1b. ๐‘Ž๐‘Ž ๐‘›๐‘› = 3๐‘›๐‘›+1c. ๐‘Ž๐‘Ž ๐‘›๐‘› = ๐‘›๐‘›+1๐‘›๐‘›d. ๐‘Ž๐‘Ž ๐‘›๐‘› = 1๐‘›๐‘› 2Exercise nยฐ3What is the limit of the following sequences, and determine whether they converge or diverge?a. ๐‘Ž๐‘Ž ๐‘›๐‘› = 2๐‘›๐‘›๐‘›๐‘›+1b. ๐‘Ž๐‘Ž ๐‘›๐‘› = 3 + (โˆ’1)๐‘›๐‘›c. ๐‘Ž๐‘Ž ๐‘›๐‘› = 2๐‘›๐‘›2๐‘›๐‘› โˆ’1d. ๐‘Ž๐‘Ž ๐‘›๐‘› = (โˆ’1)๐‘›๐‘›๐‘›๐‘›!e. ๐‘Ž๐‘Ž ๐‘›๐‘› = 5๐‘›๐‘›+73๐‘›๐‘›โˆ’5f. ๐‘Ž๐‘Ž ๐‘›๐‘› = ๐‘›๐‘› 2 +12๐‘›๐‘›โˆ’3Exercise nยฐ4Identify the type of the following sequences.a. ๐‘Ž๐‘Ž ๐‘›๐‘› = 2๐‘›๐‘› + 3b. ๐‘Ž๐‘Ž ๐‘›๐‘› = 2๐‘›๐‘›Exercise nยฐ5Generate the general term of the following sequence.โˆ’ 11 , 32 , โˆ’ 76 , 1524 , โˆ’ 31120 , โ€ฆExercise nยฐ6Find the general term of the following sequence.Given the function ๐‘“๐‘“(๐‘ฅ๐‘ฅ) = ๐‘’๐‘’ ๐‘ฅ๐‘ฅ3 ๐‘Ž๐‘Ž ๐‘›๐‘› = ๐‘“๐‘“(๐‘›๐‘›โˆ’1) (0)Exercise nยฐ7Applying lโ€™Hรดpitalโ€™s rule, evaluate lim๐‘›๐‘›โ†’โˆž(๐‘›๐‘›+1)๐‘’๐‘’ ๐‘›๐‘›Exercise nยฐ8Applying the squeeze theorem, determine the convergence or divergence of the following sequences:a. ๐‘Ž๐‘Ž ๐‘›๐‘› = sin ๐‘›๐‘›๐‘›๐‘› 2b. ๐‘Ž๐‘Ž ๐‘›๐‘› = (โˆ’1)๐‘›๐‘› โˆ™ 1๐‘›๐‘›c. ๐‘Ž๐‘Ž ๐‘›๐‘› = ๐‘›๐‘›!๐‘›๐‘› ๐‘›๐‘›Exercise nยฐ9Investigate whether the following sequences are increasing, decreasing or neither.a. ๐‘Ž๐‘Ž ๐‘›๐‘› = ๐‘›๐‘›๐‘›๐‘›+1b. ๐‘Ž๐‘Ž ๐‘›๐‘› = ๐‘›๐‘›!๐‘’๐‘’ ๐‘›๐‘› , for ๐‘›๐‘› โ‰ฅ 2Exercise nยฐ10Show that the following sequence is bounded.๐‘Ž๐‘Ž ๐‘›๐‘› = 3 โˆ’ 4๐‘›๐‘› 2๐‘›๐‘› 2 + 1

area of convergence

Per quali ๐‘ฅ reali รจ verificata la disequazione โˆš๐‘ฅ2 โˆ’ 1 > 2๐‘ฅ ?A. ๐‘ฅ โ‰ฅ โˆ’1 โ˜› pagina 107B. ๐‘ฅ โ‰ค โˆ’1 โ˜› pagina 125C. โˆ’1 < ๐‘ฅ < 1 โ˜› pagina 93D. per nessun ๐‘ฅ reale โ˜› pagina 124E. ๐‘ฅ โ‰ฅ 1

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